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Perimeter of a Triangleb1

If a, \ b, \ c\   are the lengths of the sides of any triangle. Then:

  1. Perimeter of a triangle = (a+b+c)  units
  2. Area of the triangle = \sqrt{(s(s-a)(s-b)(s-c)}  \ units.

where s=\frac{1}{2}(a+b+c) .This is also known as  Heron's \ Formula

Area of a Triangle

Refer to the adjoining figure. If b is the base and h is the height, then

Area\ of\ triangle = \frac{1}{2}(base \times height) = \frac{1}{2}(b \times h)

Note: If you could take any side as the base, then the corresponding height is the

would be the length of the perpendicular to this side from the opposite vertex.

Area of Right Angled Trianglem16x

Let the triangle be ABC, with B = 90. Please refer to the adjoining figure.

Area \ of \ triangle = \frac{1}{2}(BC \times AB)  


Area of an Equilateral triangleb2

In an equilateral triangle, all three sides are equal.

Let us say the side = a  unit.

  1. Height of an equilateral triangle = \frac{\sqrt{3}}{2}a  units
  2. Area of an equilateral triangle with side a \  is\ \frac{\sqrt{3}}{2}a^2  units


Perimeter and Area of Rectangleb3

If the sides of a rectangle arel  units and b units (refer to adjoining figure), then

  1. Perimeter of rectangle = 2(l+b)  units
  2. Area of rectangle = (l \times b)   sq. units
  3. Diagonal of a rectangle (d) = \sqrt{(l^2+b^2)} units

Perimeter and Area of a Squareb4

If the sides of a square is a  units, then

  1. Perimeter  = 4a  units
  2. Area = a^2 units
  3. Diagonal of a square = a \sqrt{2}  units


Area of a Parallelogramb5

Let ABCD be a Parallelogram with base b  and height h units. Let AC be the diagonal. Refer to the adjoining figure.

Area = (b \times h) sq. units.


Area of a Rhombusb6

Please refer to the adjoin diagram. Let d1 \ and\ d2  are the diagonals of the Rhombus. We know that the diagonals intersect at right angles and bisect each other.

Area\ of\ Rhombus= \frac{1}{2} \times (product\ of\ diagonals) = \frac{1}{2} \times (AC \times DB)   sq. units


Area of a Trapeziumb7

Please refer to the adjoining figure.  AB \parallel DC

Area\ of\ Trapezium \  ABCD \\= \frac{1}{2} \times (sum \ of \ the \ parallel \ sides) \times (distance\ between\ them)  \\= \frac{1}{2} \times (AB + DC) \times (h)   sq. units


Circumference and Area of a Circleb8

Let the circle be of radius r

  1. Circumference of the circle = 2\pi r = \pi d  
  2. Area of the circle = \pi r^2

Area of a Ring (shaded area)

Refer to the adjoining figure. The radius of the larger circle is R and that of the smaller circle is r.  Area of the ring is the shaded area.

  1. Area\ of\ the\ ring=\pi R^2 - \pi r^2 = \pi(R^2-r^2) = \pi(R+r)(R-r)